## If the vertical of a triangle ABC are A(2,-4)B(3,3) and c(-1,5) find the equation of the straight line along from the vertex B

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## Answers ( )

Answer:Let mid point BC be D, so,D=(23−1,23+5)=(1,4)

Equation of AD ⟹y−4=(x−1)(1−24−(−4))

⟹y=−8x+12

Slope of AC⟹−1−25−(−4)=−3

Slope of line is perpendicular to AC=−3−1=31

So, eqaution of at\ltitude ⟹y−3=31(x−3)⟹3y=x+6